(2x^2+2x-3)(2x+1)=0

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Solution for (2x^2+2x-3)(2x+1)=0 equation: 


Simplifying
(2x2 + 2x + -3)(2x + 1) = 0

Reorder the terms:
(-3 + 2x + 2x2)(2x + 1) = 0

Reorder the terms:
(-3 + 2x + 2x2)(1 + 2x) = 0

Multiply (-3 + 2x + 2x2) * (1 + 2x)
(-3(1 + 2x) + 2x * (1 + 2x) + 2x2 * (1 + 2x)) = 0
((1 * -3 + 2x * -3) + 2x * (1 + 2x) + 2x2 * (1 + 2x)) = 0
((-3 + -6x) + 2x * (1 + 2x) + 2x2 * (1 + 2x)) = 0
(-3 + -6x + (1 * 2x + 2x * 2x) + 2x2 * (1 + 2x)) = 0
(-3 + -6x + (2x + 4x2) + 2x2 * (1 + 2x)) = 0
(-3 + -6x + 2x + 4x2 + (1 * 2x2 + 2x * 2x2)) = 0
(-3 + -6x + 2x + 4x2 + (2x2 + 4x3)) = 0

Combine like terms: -6x + 2x = -4x
(-3 + -4x + 4x2 + 2x2 + 4x3) = 0

Combine like terms: 4x2 + 2x2 = 6x2
(-3 + -4x + 6x2 + 4x3) = 0

Solving
-3 + -4x + 6x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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